Module A5 · CSEC Chemistry
Structure & Bonding

Ionic, covalent, and metallic bonds — plus crystal structures, diamond, graphite, and the valency method for writing formulae.

Section 1 — Why Do Atoms Bond?

Atoms form chemical bonds to achieve a full outer electron shell — the same stable configuration as the noble gases (Group 0). This is called the noble gas configuration. Atoms achieve stability by losing, gaining, or sharing valence electrons.

Ionic

Metal + Non-metal

Electrons are TRANSFERRED. Metal loses electrons → cation (+). Non-metal gains electrons → anion (−). Electrostatic attraction between ions.

Examples: NaCl, MgO, CaCl₂, Al₂O₃

Covalent

Non-metal + Non-metal

Electrons are SHARED in pairs. Each shared pair = 1 covalent bond. Single, double, or triple bonds possible.

Examples: H₂O, CO₂, CH₄, N₂, HCl

Metallic

Metal + Metal

Valence electrons become DELOCALISED — free to roam. 'Sea' of mobile electrons surrounds positive cations.

Examples: Cu, Fe, Na, Mg, Al, Au

🧠 Memory Trick Metal + Non-metal = Ionic (Transfer). Non-metal + Non-metal = Covalent (Share). Metal + Metal = Metallic (Delocalised). ICM — Ionic, Covalent, Metallic.

Section 2 — Chemical Formulae & Valency

The valency of an element tells you how many bonds it forms. Use the valency method to write formulae: the number of atoms of each element is swapped from the other element's valency.

Valency Rule Groups I–IV: valency = group number (Na=1, Mg=2, Al=3, C=4). Groups V–VII: valency = 8 minus group number (N=3, O=2, Cl=1). The sum of (atoms × valency) must be EQUAL for both elements.
CompoundElement 1 (valency)Element 2 (valency)WorkingFormula
Magnesium nitrideMg (2)N (3)Mg₃ × 2 = 6, N₂ × 3 = 6Mg₃N₂
Aluminium oxideAl (3)O (2)Al₂ × 3 = 6, O₃ × 2 = 6Al₂O₃
Iron(III) bromideFe (3)Br (1)Fe × 3 = 3, Br₃ × 1 = 3FeBr₃
Carbon dioxideC (4)O (2)C₂O₄ → simplify → CO₂CO₂
Calcium chlorideCa (2)Cl (1)Ca × 2 = 2, Cl₂ × 1 = 2CaCl₂

Section 3 — Ionic Bonding

Ionic bonding involves the transfer of valence electrons from a metal to a non-metal. The metal loses electrons and becomes a positive cation; the non-metal gains electrons and becomes a negative anion. The strong electrostatic force between oppositely-charged ions IS the ionic bond.

Worked Examples of Ionic Bond Formation

CompoundMetal IonNon-metal IonFormula
Sodium chlorideNa loses 1e⁻ → Na⁺Cl gains 1e⁻ → Cl⁻NaCl
Magnesium fluorideMg loses 2e⁻ → Mg²⁺F gains 1e⁻ → F⁻ (need 2F)MgF₂
Aluminium oxideAl loses 3e⁻ → Al³⁺ (need 2 Al)O gains 2e⁻ → O²⁻ (need 3 O)Al₂O₃
Potassium nitrideK loses 1e⁻ → K⁺ (need 3 K)N gains 3e⁻ → N³⁻K₃N
Properties of Ionic Compounds High melting point — strong ionic bonds need lots of energy to break (NaCl melts at 801°C). Hard but brittle — ions shift under pressure, like charges repel, lattice shatters. Soluble in water — polar water molecules attract ions apart. Conducts electricity ONLY when molten or dissolved — ions must be free to move. Does NOT conduct when solid (ions fixed in lattice).
🌍 Real World — Table Salt NaCl is so essential that Roman soldiers were partly paid in it — giving us the word 'salary' from the Latin 'salarium'. Today 300 million tonnes are produced annually for food, chemical manufacturing and water treatment. Every ionic property you learn about is on your kitchen table!

Section 4 — Covalent Bonding

Covalent bonding occurs between two or more non-metal atoms. Instead of transferring electrons, atoms share pairs of valence electrons. Each shared pair forms one covalent bond. The resulting particles are called molecules.

Bond TypeShared PairsBond SymbolExamples
Single covalent1 pair (2 electrons)H₂, HCl, H₂O, CH₄, NH₃, Cl₂
Double covalent2 pairs (4 electrons)=O₂, CO₂, C₂H₄ (ethene)
Triple covalent3 pairs (6 electrons)N₂, C₂H₂ (ethyne)

Key Covalent Molecules — Quick Reference

MoleculeBond TypeValence Electrons UsedStructural Formula
Cl₂SingleCl(7) needs 1 more — shares 1 pair with ClCl—Cl
H₂O2× SingleO(6) needs 2 — two H atoms share 1 pair eachH—O—H
CH₄4× SingleC(4) needs 4 — four H atoms share 1 pair eachH₃C—H (4 bonds)
O₂DoubleO(6) needs 2 — two O atoms share 2 pairsO=O
CO₂2× DoubleC(4) needs 4 — double bond with each OO=C=O
N₂TripleN(5) needs 3 — two N atoms share 3 pairsN≡N
💧 Polar vs Non-Polar Polar molecules have atoms that attract shared electrons with different strengths → uneven charge distribution. Examples: H₂O, HCl, NH₃. Non-polar: atoms attract equally. Examples: H₂, O₂, N₂, CO₂ (symmetric), CH₄, CCl₄.
🌡️ CO₂ & Climate CO₂ has two double covalent bonds (O=C=O). Though non-polar overall, it absorbs infrared radiation — the greenhouse effect. Human activity adds ~37 billion tonnes of CO₂ annually. A single covalent molecule is linked to global climate change!

Section 5 — Metallic Bonding

In metals, valence electrons become delocalised — free to move throughout a 'sea' of electrons surrounding positive metal cations. The strong electrostatic attraction between the positive cations and the electron sea IS the metallic bond.

PropertyExplanation Using Metallic Bonding
High melting/boiling pointsStrong electrostatic forces between cations and delocalised electrons require large amounts of energy to break. E.g. iron melts at 1538°C.
Good electrical conductorsDelocalised electrons are free to move. When voltage is applied, they flow, carrying electric current (e.g. copper wires).
Good heat conductorsMobile electrons carry kinetic energy (heat) rapidly through the metal lattice.
Malleable (can be hammered flat)All atoms are the same type and size. Layers can slide past each other without breaking metallic bonds.
Ductile (drawn into wires)Layers of atoms slide along the direction of applied force without bonds breaking.
Shiny appearanceThe delocalised electron sea reflects light from the surface.

Section 6 — Four Crystal Types

Crystal TypeParticlesForcesMelting PointConductivityExamples
IonicCations & anionsStrong ionic bondsHIGH (NaCl = 801°C)Only when molten or dissolved in waterNaCl, KBr, MgO
Simple MolecularSmall moleculesWEAK intermolecular forces (strong covalent bonds within)LOW (Ice = 0°C)NeverIce, I₂, CO₂, glucose
Giant MolecularNon-metal atomsStrong covalent bonds throughout 3D latticeVERY HIGH (Diamond = 3550°C)Usually none (except graphite)Diamond, graphite, SiO₂
MetallicCations + delocalised electronsStrong metallic bondsHIGH (varies)Excellent in all statesCu, Fe, Al, Na

Section 7 — Diamond & Graphite: Allotropes of Carbon

Allotropy Allotropes are different structural forms of the SAME element in the SAME physical state. Diamond and graphite are allotropes of carbon — they have identical chemical properties (both burn in O₂ to form CO₂) but very different physical properties.
PropertyDiamondGraphite
StructureEach C atom bonded covalently to 4 others in a tetrahedral giant molecular latticeEach C atom bonded to 3 others in hexagonal rings forming flat layers. Weak van der Waals forces between layers
HardnessEXTREMELY HARD — hardest known natural substanceSOFT & flaky — layers slide easily
Electrical conductivityDoes NOT conduct — all 4 valence electrons used in bonds, none free to moveCONDUCTS — 4th valence electron on each C is delocalised and free to move between layers
Lubricating powerNone — atoms rigidly bonded in all directionsEXCELLENT lubricant — layers slide over each other
Melting point~3550°C — enormous energy to break all covalent bonds~3600°C — strong covalent bonds within layers
Real-world usesJewellery, diamond drill bits, glass cutters, surgical scalpelsPencil 'lead', electrodes in electrolysis, crucibles, solid lubricant
💡 Top Exam Question — Graphite Conductivity Always state: "Each carbon atom forms 3 covalent bonds, leaving 1 valence electron per carbon atom delocalised. These delocalised electrons are free to move between the layers and carry electric charge." This is worth full marks on any 3-mark question.

Section 8 — Resources & Simulations

Section 9 — CSEC Practice Questions

Question 1 — Multiple Choice
Which of the following compounds contains ONLY covalent bonds?
(A) NaCl   (B) MgO   (C) NH₃   (D) KF
+

1 NaCl = Na (metal) + Cl (non-metal) → ionic. MgO = Mg (metal) + O (non-metal) → ionic. KF = K (metal) + F (non-metal) → ionic.

2 NH₃ = N (non-metal) + H (non-metal) → non-metals only → covalent bonding.

✅ Answer: (C) NH₃ — nitrogen and hydrogen are both non-metals, forming covalent bonds by sharing electron pairs.
Question 2 — Structured
Explain why solid sodium chloride does not conduct electricity, but sodium chloride dissolved in water does.
+

1 Solid NaCl: Na⁺ and Cl⁻ ions are held in fixed positions in the ionic crystal lattice by strong electrostatic forces of attraction. They cannot move, so they cannot carry an electric charge — no conduction.

2 NaCl in water: Water molecules attract and separate the ions. The Na⁺ and Cl⁻ ions become free to move throughout the solution. Mobile charged particles (ions) can carry charge from one electrode to the other — conduction occurs.

✅ Key principle: for a substance to conduct electricity, it must have charged particles that are FREE to move. In solid NaCl the ions are fixed; in solution they are free.
Question 3 — Structured
Compare the structure and bonding of diamond and graphite. Use this to explain why graphite conducts electricity but diamond does not. [6 marks]
+

1 Diamond: Each carbon atom is covalently bonded to 4 other carbon atoms in a tetrahedral arrangement. A giant covalent 3D lattice forms throughout the crystal. All 4 valence electrons of each carbon are used in covalent bonds — there are no free electrons.

2 Graphite: Each carbon atom is covalently bonded to only 3 other carbon atoms, forming hexagonal rings in flat layers. The 4th valence electron from each carbon atom is delocalised — free to move between layers throughout the structure.

3 Conductivity: Diamond has no free (delocalised) electrons, so charge cannot flow — it does not conduct. Graphite has delocalised electrons that can move freely between layers when a voltage is applied, carrying electric charge — it conducts.

✅ Diamond = 4 bonds per C, no free electrons → no conductivity. Graphite = 3 bonds per C, 1 delocalised electron per C → conducts electricity.
Question 4 — Formulae
Write the empirical formulae for: (a) calcium nitride (b) iron(III) oxide (c) aluminium sulfide.
+

a Calcium nitride: Ca²⁺ and N³⁻. To balance: 2 Ca (losing 2e⁻ each = 4e⁻ total), 3 N (gaining... wait — 3 Ca × 2 = 6 and 2 N × 3 = 6). Formula: Ca₃N₂

b Iron(III) oxide: Fe³⁺ and O²⁻. 2 Fe × 3 = 6, 3 O × 2 = 6. Formula: Fe₂O₃

c Aluminium sulfide: Al³⁺ and S²⁻. 2 Al × 3 = 6, 3 S × 2 = 6. Formula: Al₂S₃

✅ (a) Ca₃N₂   (b) Fe₂O₃   (c) Al₂S₃
Question 5 — Properties
A solid substance has a high melting point, does not conduct electricity in the solid state but conducts when dissolved in water, and is hard but brittle. What type of bonding and crystal structure does it have? Give one example.
+

1 High melting point → strong forces of attraction between particles.

2 Does NOT conduct as solid but DOES conduct when dissolved → ions present, but only free to move in solution (not when fixed in lattice). This is the hallmark of ionic bonding.

3 Hard but brittle → ionic crystal lattice; layers shift under pressure, like charges come adjacent and repel, shattering the lattice.

✅ Ionic bonding; ionic crystal lattice. Example: Sodium chloride (NaCl), or any Group I/II halide or oxide.