Module A6 · CSEC Chemistry
Chemical Reactions & Equations

From balancing atoms to writing ionic equations and identifying all 7 reaction types — master the language of chemistry.

Section 1 — What Is a Chemical Equation?

A chemical equation is a shorthand representation of a chemical reaction using symbols and formulae. It's the universal language of chemistry — a chemist anywhere in the world can read the same equation.

⚖️ The Golden Rule Reactants (left) → Products (right). The arrow means "reacts to form" or "produces." Atoms are NEVER created or destroyed — they just rearrange. So the number of each atom must be the same on both sides.

Conventions You Must Know

  • 1Reactants on the LEFT, products on the RIGHT, separated by →
  • 2State symbols after each formula: (s) solid · (l) liquid · (g) gas · (aq) aqueous solution
  • 3Conditions (temperature, pressure, catalyst) go ABOVE the arrow
  • 4Use double arrow for reversible reactions
  • 5NEVER change a formula to balance — only change the coefficients (numbers in front)
🧠 The 7 Diatomic Elements H₂ · N₂ · O₂ · F₂ · Cl₂ · Br₂ · I₂ — these always exist as pairs in their free state. Memory trick: HOFBrINCl ("Hoff-brinkle"). Never write just "Cl" or "O" for the free element — always Cl₂ and O₂!

Section 2 — Balancing Chemical Equations

Step-by-Step Balancing Method

  • 1Write the correct formulae of all reactants and products with state symbols.
  • 2Count atoms on each side.
  • 3Balance elements that appear in only one compound first. Leave free-state elements (H₂, O₂) for last.
  • 4If H or O are in compounds, balance H second-to-last and O last.
  • 5Adjust coefficients (numbers in front) — NEVER change subscripts!
  • 6Check coefficients are in the lowest possible ratio.

Worked Example 1 — Mg burns in O₂

Unbalanced: Mg(s) + O₂(g) → MgO(s) Count: Mg=1, O=2 (left) Mg=1, O=1 (right) ❌ Fix O: → 2MgO(s) [now Mg=1 vs 2] Fix Mg: 2Mg(s) + O₂(g) → 2MgO(s) Check: Mg=2, O=2 both sides ✅ BALANCED!

Worked Example 2 — Propane (C₃H₈) burns

Unbalanced: C₃H₈(g) + O₂(g) → CO₂(g) + H₂O(g) Balance C: → 3CO₂(g) Balance H: → 4H₂O(g) Count O on right: 6+4 = 10 Fix O₂: put 5 in front of O₂ BALANCED: C₃H₈(g) + 5O₂(g) → 3CO₂(g) + 4H₂O(g) ✅

Section 3 — State Symbols & Solubility Rules

Whether an ionic compound is written as (aq) or (s) depends on its solubility in water. You need to know these rules to correctly label equations.

Compound / IonSolubilityImportant Exceptions
All Group I (Li, Na, K) compounds✅ SolubleNone
Ammonium (NH₄⁺) compounds✅ SolubleNone
Nitrates (NO₃⁻)✅ SolubleNone
Chlorides, Bromides, Iodides✅ SolubleAgCl, PbCl₂ — insoluble
Sulfates (SO₄²⁻)✅ SolubleBaSO₄, PbSO₄ — insoluble; CaSO₄ — slightly soluble
Carbonates & Phosphates❌ InsolubleGroup I + ammonium carbonates/phosphates are soluble
Most Hydroxides (OH⁻)❌ InsolubleNaOH, KOH soluble; Ba(OH)₂ moderately; Ca(OH)₂ slightly
🌍 Caribbean Connection — Hard Water Hard water in the Caribbean contains dissolved Ca²⁺ and Mg²⁺ ions. These form insoluble CaCO₃ (limescale) in pipes, kettles, and showers. The solubility rules you just learned explain exactly why this happens — calcium carbonate is insoluble!

Section 4 — Ionic Equations

Ionic equations show ONLY the ions that actually change during a reaction. Ions that don't change are called spectator ions — they get cancelled out.

4 Steps to Write an Ionic Equation

  • 1Write the balanced molecular equation.
  • 2Rewrite it, splitting ALL (aq) ionic compounds into their individual ions.
  • 3Cancel (cross out) spectator ions — those that appear identically on BOTH sides.
  • 4Write the final net ionic equation with only the ions that changed.

Example 1 — Lead Nitrate + Sodium Chloride

Step 1: Pb(NO₃)₂(aq) + 2NaCl(aq) → PbCl₂(s) + 2NaNO₃(aq) Step 2 (split aq): Pb²⁺ + 2NO₃⁻ + 2Na⁺ + 2Cl⁻ → PbCl₂(s) + 2Na⁺ + 2NO₃⁻ Step 3: Cancel Na⁺ and NO₃⁻ (spectators) Step 4 — Net ionic equation: Pb²⁺(aq) + 2Cl⁻(aq) → PbCl₂(s) ✅

Example 2 — KOH + H₂SO₄ (Neutralisation)

Step 1: 2KOH(aq) + H₂SO₄(aq) → K₂SO₄(aq) + 2H₂O(l) Step 2 (split aq): 2K⁺ + 2OH⁻ + 2H⁺ + SO₄²⁻ → 2K⁺ + SO₄²⁻ + 2H₂O(l) Step 3: Cancel K⁺ and SO₄²⁻ (spectators) Step 4 — Net ionic equation: OH⁻(aq) + H⁺(aq) → H₂O(l) ✅ (All neutralisations!)

Section 5 — The 7 Types of Chemical Reactions

⚡ 1 — Synthesis

Two or more substances combine to form a SINGLE product.

Pattern: A + B → AB

2Mg(s) + O₂(g) → 2MgO(s)
💥 2 — Decomposition

One reactant breaks down into two or more products. Can be thermal or electrolytic.

Pattern: AB → A + B

CaCO₃(s) →(heat) CaO(s) + CO₂(g)
🔄 3 — Single Displacement

A more reactive element displaces a less reactive one from a compound.

Pattern: A + BX → AX + B

Mg(s) + CuSO₄(aq) → MgSO₄(aq) + Cu(s)
⬇️ 4 — Ionic Precipitation

Two ionic solutions exchange ions; one product is INSOLUBLE (precipitate).

Pattern: AX + BY → AY↓ + BX

AgNO₃(aq) + KBr(aq) → AgBr(s) + KNO₃(aq)
🧪 5 — Neutralisation

Acid + base/alkali → salt + water.

Pattern: Acid + Base → Salt + H₂O

NaOH(aq) + HCl(aq) → NaCl(aq) + H₂O(l)
🔥 6 — Redox

One reactant is OXIDISED and another is REDUCED (electron transfer).

Memory: OIL RIG (Oxidation Is Loss, Reduction Is Gain)

CH₄(g) + 2O₂(g) → CO₂(g) + 2H₂O(g)
⇌ 7 — Reversible

Reaction can proceed in BOTH directions. Products can reform reactants.

Pattern: A + B ⇌ C + D

NH₄Cl(s) ⇌ NH₃(g) + HCl(g)

Section 6 — Resources & Simulations

Section 7 — CSEC Practice Questions

Question 1 — Balancing
Balance the following equations and include state symbols:
(a) Al(s) + O₂(g) → Al₂O₃(s)
(b) Fe(s) + Cl₂(g) → FeCl₃(s)
(c) N₂(g) + H₂(g) ⇌ NH₃(g)
+

a Al needs 2 on right (Al₂O₃), so 4 Al on left. O₂: right has 3 O, so put 3/2 O₂ → multiply all by 2: 4Al(s) + 3O₂(g) → 2Al₂O₃(s)

Check: Al = 4 both sides ✅ O = 6 both sides ✅

b FeCl₃ needs 3 Cl. Cl₂ comes in pairs, so need 3 Cl₂ to give 6 Cl → 2 FeCl₃: 2Fe(s) + 3Cl₂(g) → 2FeCl₃(s)

c NH₃ has 1 N and 3 H. Need 2 NH₃ to use 1 N₂. Then H side needs 3 H₂: N₂(g) + 3H₂(g) ⇌ 2NH₃(g)

✅ (a) 4Al + 3O₂ → 2Al₂O₃   (b) 2Fe + 3Cl₂ → 2FeCl₃   (c) N₂ + 3H₂ ⇌ 2NH₃
Question 2 — Solubility
State whether each compound is SOLUBLE or INSOLUBLE in water: (a) AgI   (b) Fe(NO₃)₃   (c) Na₂CO₃   (d) BaSO₄   (e) (NH₄)₃PO₄
+

a AgI — Iodides are usually soluble, BUT AgI is an exception → INSOLUBLE

b Fe(NO₃)₃ — all nitrates are soluble → SOLUBLE

c Na₂CO₃ — Group I compounds are all soluble (Na is Group I) → SOLUBLE

d BaSO₄ — Sulfates are usually soluble, BUT BaSO₄ is an exception → INSOLUBLE

e (NH₄)₃PO₄ — Phosphates are usually insoluble, BUT ammonium compounds are all soluble → SOLUBLE

✅ (a) Insoluble (b) Soluble (c) Soluble (d) Insoluble (e) Soluble
Question 3 — Ionic Equation
Write the ionic equation for the reaction between barium nitrate solution and sodium sulfate solution. Include state symbols.
+

1 Write molecular equation. BaSO₄ is insoluble (exception), NaNO₃ is soluble:

Ba(NO₃)₂(aq) + Na₂SO₄(aq) → BaSO₄(s) + 2NaNO₃(aq)

2 Split all (aq) compounds into ions:

Ba²⁺(aq) + 2NO₃⁻(aq) + 2Na⁺(aq) + SO₄²⁻(aq) → BaSO₄(s) + 2Na⁺(aq) + 2NO₃⁻(aq)

3 Cancel spectator ions: Na⁺ and NO₃⁻ appear on both sides — cancel them.

✅ Net ionic equation: Ba²⁺(aq) + SO₄²⁻(aq) → BaSO₄(s)
A white precipitate of barium sulfate forms.
Question 4 — Classify the Reaction
Classify each reaction type and give a reason:
(a) Mg(NO₃)₂(s) → MgO(s) + NO₂(g) + O₂(g)
(b) Zn(s) + HCl(aq) → ZnCl₂(aq) + H₂(g)
(c) AgNO₃(aq) + MgBr₂(aq) → AgBr(s) + Mg(NO₃)₂(aq)
+

a One reactant breaks into multiple products → Decomposition. (Thermal decomposition of magnesium nitrate.)

b Zn (more reactive) displaces H from HCl → Single Displacement. Zinc displaces hydrogen because Zn is higher in the reactivity series than H.

c Two ionic solutions swap partners; AgBr(s) is an insoluble precipitate → Ionic Precipitation (Double Displacement).

✅ (a) Decomposition (b) Single Displacement (c) Ionic Precipitation
Question 5 — Structured (Exam Style)
When excess zinc powder is added to blue copper(II) sulfate solution, the solution becomes colourless and a pink/brown solid forms. (a) Write a balanced equation for this reaction. (b) Classify the type of reaction. (c) Write the ionic equation.
+

a Zinc displaces copper from copper(II) sulfate. Zinc sulfate is soluble (colorless), copper metal is a pink-brown solid:

Zn(s) + CuSO₄(aq) → ZnSO₄(aq) + Cu(s)

b A more reactive element (Zn) displaces a less reactive element (Cu) from a compound → Single Displacement reaction.

c Split (aq): Zn(s) + Zn²⁺(aq)? No — Zn is a solid reactant, doesn't split. Split CuSO₄ and ZnSO₄:

Zn(s) + Cu²⁺(aq) + SO₄²⁻(aq) → Zn²⁺(aq) + SO₄²⁻(aq) + Cu(s)

Cancel SO₄²⁻ (spectator ion):

✅ Net ionic equation: Zn(s) + Cu²⁺(aq) → Zn²⁺(aq) + Cu(s)